132445412001031 has 4 divisors (see below), whose sum is σ = 139416223159000. Its totient is φ = 125474600843064.

The previous prime is 132445412001013. The next prime is 132445412001041. The reversal of 132445412001031 is 130100214544231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132445412001031 - 2⁹ = 132445412000519 is a prime.

It is a super-3 number, since 3×132445412001031³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132445412000984 and 132445412001002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132445412001041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3485405578956 + ... + 3485405578993.

It is an arithmetic number, because the mean of its divisors is an integer number (34854055789750).

Almost surely, 2^{132445412001031} is an apocalyptic number.

132445412001031 is a deficient number, since it is larger than the sum of its proper divisors (6970811157969).

132445412001031 is an equidigital number, since it uses as much as digits as its factorization.

132445412001031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6970811157968.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 132445412001031 its reverse (130100214544231), we get a palindrome (262545626545262).

The spelling of 132445412001031 in words is "one hundred thirty-two trillion, four hundred forty-five billion, four hundred twelve million, one thousand, thirty-one".