Base | Representation |
---|---|
bin | 11000101010111010… |
… | …00111000010010111 |
3 | 1021012001112022120211 |
4 | 30111131013002113 |
5 | 204111140320143 |
6 | 10030135110251 |
7 | 646135255633 |
oct | 142535070227 |
9 | 37161468524 |
10 | 13244854423 |
11 | 5687414189 |
12 | 2697812387 |
13 | 1331032288 |
14 | 8d90a5dc3 |
15 | 527bbb49d |
hex | 315747097 |
13244854423 has 2 divisors, whose sum is σ = 13244854424. Its totient is φ = 13244854422.
The previous prime is 13244854417. The next prime is 13244854463. The reversal of 13244854423 is 32445844231.
13244854423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (13244854463) can be obtained adding 13244854423 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13244854423 - 25 = 13244854391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13244854463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622427211 + 6622427212.
It is an arithmetic number, because the mean of its divisors is an integer number (6622427212).
Almost surely, 213244854423 is an apocalyptic number.
13244854423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13244854423 is an equidigital number, since it uses as much as digits as its factorization.
13244854423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 368640, while the sum is 40.
The spelling of 13244854423 in words is "thirteen billion, two hundred forty-four million, eight hundred fifty-four thousand, four hundred twenty-three".
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