13250111343501 has 4 divisors (see below), whose sum is σ = 17666815124672. Its totient is φ = 8833407562332.

The previous prime is 13250111343493. The next prime is 13250111343533. The reversal of 13250111343501 is 10534311105231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13250111343501 - 2³ = 13250111343493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13250111343401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2208351890581 + ... + 2208351890586.

It is an arithmetic number, because the mean of its divisors is an integer number (4416703781168).

Almost surely, 2^{13250111343501} is an apocalyptic number.

It is an amenable number.

13250111343501 is a deficient number, since it is larger than the sum of its proper divisors (4416703781171).

13250111343501 is an equidigital number, since it uses as much as digits as its factorization.

13250111343501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4416703781170.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 13250111343501 its reverse (10534311105231), we get a palindrome (23784422448732).

The spelling of 13250111343501 in words is "thirteen trillion, two hundred fifty billion, one hundred eleven million, three hundred forty-three thousand, five hundred one".