Base | Representation |
---|---|
bin | 10011010010000010000… |
… | …101010000011101110110 |
3 | 11200200010210010020212022 |
4 | 103102002011100131312 |
5 | 133202131234442124 |
6 | 2452413401353142 |
7 | 164505352041413 |
oct | 23220205203566 |
9 | 4620123106768 |
10 | 1325032343414 |
11 | 470a4123a30a |
12 | 1949727987b2 |
13 | 97c47246470 |
14 | 481bbd5110a |
15 | 24701885c5e |
hex | 13482150776 |
1325032343414 has 8 divisors (see below), whose sum is σ = 2140436862480. Its totient is φ = 611553389256.
The previous prime is 1325032343407. The next prime is 1325032343417. The reversal of 1325032343414 is 4143432305231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×13250323434142 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325032343417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25481391194 + ... + 25481391245.
It is an arithmetic number, because the mean of its divisors is an integer number (267554607810).
Almost surely, 21325032343414 is an apocalyptic number.
1325032343414 is a deficient number, since it is larger than the sum of its proper divisors (815404519066).
1325032343414 is a wasteful number, since it uses less digits than its factorization.
1325032343414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50962782454.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 1325032343414 its reverse (4143432305231), we get a palindrome (5468464648645).
The spelling of 1325032343414 in words is "one trillion, three hundred twenty-five billion, thirty-two million, three hundred forty-three thousand, four hundred fourteen".
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