Base | Representation |
---|---|
bin | 111101101101010001… |
… | …0101101011100111011 |
3 | 110200001020101110220200 |
4 | 1323122202231130323 |
5 | 4132342440113120 |
6 | 140513220053243 |
7 | 12400600412250 |
oct | 1733242553473 |
9 | 420036343820 |
10 | 132515551035 |
11 | 5122163492a |
12 | 21823234223 |
13 | c65b0ba37a |
14 | 65b1607427 |
15 | 36a8b11e90 |
hex | 1eda8ad73b |
132515551035 has 48 divisors (see below), whose sum is σ = 262945612800. Its totient is φ = 60477318720.
The previous prime is 132515551027. The next prime is 132515551061. The reversal of 132515551035 is 530155515231.
132515551035 is a `hidden beast` number, since 1 + 32 + 515 + 5 + 5 + 103 + 5 = 666.
It is not a de Polignac number, because 132515551035 - 23 = 132515551027 is a prime.
It is a super-2 number, since 2×1325155510352 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 162471 + ... + 539840.
It is an arithmetic number, because the mean of its divisors is an integer number (5478033600).
Almost surely, 2132515551035 is an apocalyptic number.
132515551035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132515551035 is a deficient number, since it is larger than the sum of its proper divisors (130430061765).
132515551035 is a wasteful number, since it uses less digits than its factorization.
132515551035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 702928 (or 702925 counting only the distinct ones).
The product of its (nonzero) digits is 56250, while the sum is 36.
The spelling of 132515551035 in words is "one hundred thirty-two billion, five hundred fifteen million, five hundred fifty-one thousand, thirty-five".
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