Base | Representation |
---|---|
bin | 111101101101011001… |
… | …1110011111011111111 |
3 | 110200001112211020110011 |
4 | 1323122303303323333 |
5 | 4132400112042142 |
6 | 140513500124051 |
7 | 12400653463252 |
oct | 1733263637377 |
9 | 420045736404 |
10 | 132520034047 |
11 | 51224116aa5 |
12 | 21824836627 |
13 | c65bcc9a3b |
14 | 65b2053099 |
15 | 36a91ea417 |
hex | 1edacf3eff |
132520034047 has 2 divisors, whose sum is σ = 132520034048. Its totient is φ = 132520034046.
The previous prime is 132520034029. The next prime is 132520034131. The reversal of 132520034047 is 740430025231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132520034047 - 211 = 132520031999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132520034147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66260017023 + 66260017024.
It is an arithmetic number, because the mean of its divisors is an integer number (66260017024).
Almost surely, 2132520034047 is an apocalyptic number.
132520034047 is a deficient number, since it is larger than the sum of its proper divisors (1).
132520034047 is an equidigital number, since it uses as much as digits as its factorization.
132520034047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 31.
Adding to 132520034047 its reverse (740430025231), we get a palindrome (872950059278).
The spelling of 132520034047 in words is "one hundred thirty-two billion, five hundred twenty million, thirty-four thousand, forty-seven".
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