Base | Representation |
---|---|
bin | 111101101101011001… |
… | …1110011111101010011 |
3 | 110200001112211020120021 |
4 | 1323122303303331103 |
5 | 4132400112043011 |
6 | 140513500124311 |
7 | 12400653463432 |
oct | 1733263637523 |
9 | 420045736507 |
10 | 132520034131 |
11 | 51224117071 |
12 | 21824836697 |
13 | c65bcc9aa4 |
14 | 65b2053119 |
15 | 36a91ea471 |
hex | 1edacf3f53 |
132520034131 has 2 divisors, whose sum is σ = 132520034132. Its totient is φ = 132520034130.
The previous prime is 132520034047. The next prime is 132520034147. The reversal of 132520034131 is 131430025231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132520034131 - 215 = 132520001363 is a prime.
It is a super-2 number, since 2×1325200341312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132520034096 and 132520034105.
It is not a weakly prime, because it can be changed into another prime (132520034161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66260017065 + 66260017066.
It is an arithmetic number, because the mean of its divisors is an integer number (66260017066).
Almost surely, 2132520034131 is an apocalyptic number.
132520034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132520034131 is an equidigital number, since it uses as much as digits as its factorization.
132520034131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 132520034131 its reverse (131430025231), we get a palindrome (263950059362).
The spelling of 132520034131 in words is "one hundred thirty-two billion, five hundred twenty million, thirty-four thousand, one hundred thirty-one".
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