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132531431 is a prime number
BaseRepresentation
bin1111110011001…
…00010011100111
3100020101021221112
413321210103213
5232412001211
621052335235
73166333004
oct771442347
9306337845
10132531431
11688a090a
123847451b
13215c3a86
141385c8ab
15b97d88b
hex7e644e7

132531431 has 2 divisors, whose sum is σ = 132531432. Its totient is φ = 132531430.

The previous prime is 132531419. The next prime is 132531433. The reversal of 132531431 is 134135231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132531431 - 210 = 132530407 is a prime.

It is a super-2 number, since 2×1325314312 = 35129160405815522, which contains 22 as substring.

Together with 132531433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132531397 and 132531406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132531433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66265715 + 66265716.

It is an arithmetic number, because the mean of its divisors is an integer number (66265716).

Almost surely, 2132531431 is an apocalyptic number.

132531431 is a deficient number, since it is larger than the sum of its proper divisors (1).

132531431 is an equidigital number, since it uses as much as digits as its factorization.

132531431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 23.

The square root of 132531431 is about 11512.2296276612. The cubic root of 132531431 is about 509.8467192827.

Adding to 132531431 its reverse (134135231), we get a palindrome (266666662).

The spelling of 132531431 in words is "one hundred thirty-two million, five hundred thirty-one thousand, four hundred thirty-one".