Base | Representation |
---|---|
bin | 111101101110000110… |
… | …0101011110000000111 |
3 | 110200010011122212022200 |
4 | 1323130030223300013 |
5 | 4132422043100320 |
6 | 140520051325543 |
7 | 12401355504342 |
oct | 1733414536007 |
9 | 420104585280 |
10 | 132543331335 |
11 | 51236289658 |
12 | 218305b08b3 |
13 | c663a95c0c |
14 | 65b5199459 |
15 | 36ab29d290 |
hex | 1edc32bc07 |
132543331335 has 24 divisors (see below), whose sum is σ = 230209718544. Its totient is φ = 70545793920.
The previous prime is 132543331303. The next prime is 132543331429. The reversal of 132543331335 is 533133345231.
132543331335 is a `hidden beast` number, since 13 + 254 + 33 + 31 + 335 = 666.
It is not a de Polignac number, because 132543331335 - 25 = 132543331303 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132543331335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2977302 + ... + 3021491.
It is an arithmetic number, because the mean of its divisors is an integer number (9592071606).
Almost surely, 2132543331335 is an apocalyptic number.
132543331335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132543331335 is a deficient number, since it is larger than the sum of its proper divisors (97666387209).
132543331335 is a wasteful number, since it uses less digits than its factorization.
132543331335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5999295 (or 5999292 counting only the distinct ones).
The product of its digits is 145800, while the sum is 36.
Adding to 132543331335 its reverse (533133345231), we get a palindrome (665676676566).
The spelling of 132543331335 in words is "one hundred thirty-two billion, five hundred forty-three million, three hundred thirty-one thousand, three hundred thirty-five".
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