Base | Representation |
---|---|
bin | 111101101110010011… |
… | …1010111000001110111 |
3 | 110200010122211010220222 |
4 | 1323130213113001313 |
5 | 4132430340334333 |
6 | 140520501244555 |
7 | 12401502111203 |
oct | 1733447270167 |
9 | 420118733828 |
10 | 132550324343 |
11 | 5123a2255a8 |
12 | 21832a0375b |
13 | c665373ba8 |
14 | 65b6099b03 |
15 | 36abbd0298 |
hex | 1edc9d7077 |
132550324343 has 8 divisors (see below), whose sum is σ = 134052427440. Its totient is φ = 131048505280.
The previous prime is 132550324327. The next prime is 132550324373. The reversal of 132550324343 is 343423055231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132550324343 - 24 = 132550324327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132550324373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 950321 + ... + 1080837.
It is an arithmetic number, because the mean of its divisors is an integer number (16756553430).
Almost surely, 2132550324343 is an apocalyptic number.
132550324343 is a deficient number, since it is larger than the sum of its proper divisors (1502103097).
132550324343 is a wasteful number, since it uses less digits than its factorization.
132550324343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142017.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 132550324343 its reverse (343423055231), we get a palindrome (475973379574).
The spelling of 132550324343 in words is "one hundred thirty-two billion, five hundred fifty million, three hundred twenty-four thousand, three hundred forty-three".
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