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132653524464451 is a prime number
BaseRepresentation
bin11110001010010111001110…
…001101000011001101000011
3122101200112221012102201011101
4132022113032031003031003
5114341343404230330301
61150044104324155231
736640620666412054
oct3612271615031503
9571615835381141
10132653524464451
11392a40533209a1
1212a65184b38b17
13590323476a5a3
1424a867174c72b
1510509513c9701
hex78a5ce343343

132653524464451 has 2 divisors, whose sum is σ = 132653524464452. Its totient is φ = 132653524464450.

The previous prime is 132653524464449. The next prime is 132653524464463. The reversal of 132653524464451 is 154464425356231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132653524464451 - 21 = 132653524464449 is a prime.

Together with 132653524464449, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 132653524464392 and 132653524464401.

It is not a weakly prime, because it can be changed into another prime (132653524464491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326762232225 + 66326762232226.

It is an arithmetic number, because the mean of its divisors is an integer number (66326762232226).

Almost surely, 2132653524464451 is an apocalyptic number.

132653524464451 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653524464451 is an equidigital number, since it uses as much as digits as its factorization.

132653524464451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472000, while the sum is 55.

The spelling of 132653524464451 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred twenty-four million, four hundred sixty-four thousand, four hundred fifty-one".