Base | Representation |
---|---|
bin | 1100000110001010010111… |
… | …1001101100011001100000 |
3 | 1202002110122000101220200022 |
4 | 3001202211321230121200 |
5 | 3220401401020104440 |
6 | 44141534151013012 |
7 | 2541615310444532 |
oct | 301424571543140 |
9 | 52073560356608 |
10 | 13300002113120 |
11 | 426855450a678 |
12 | 15a976796a168 |
13 | 756253076a98 |
14 | 33da1b557852 |
15 | 180e6c111cb5 |
hex | c18a5e6c660 |
13300002113120 has 192 divisors, whose sum is σ = 32991618401280. Its totient is φ = 5057094924288.
The previous prime is 13300002113117. The next prime is 13300002113149. The reversal of 13300002113120 is 2131120000331.
It is a super-2 number, since 2×133000021131202 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 405508562 + ... + 405541358.
It is an arithmetic number, because the mean of its divisors is an integer number (171831345840).
Almost surely, 213300002113120 is an apocalyptic number.
13300002113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13300002113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16495809200640).
13300002113120 is an abundant number, since it is smaller than the sum of its proper divisors (19691616288160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300002113120 is a wasteful number, since it uses less digits than its factorization.
13300002113120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33517 (or 33509 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13300002113120 its reverse (2131120000331), we get a palindrome (15431122113451).
The spelling of 13300002113120 in words is "thirteen trillion, three hundred billion, two million, one hundred thirteen thousand, one hundred twenty".
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