13300012111 has 4 divisors (see below), whose sum is σ = 13300437952. Its totient is φ = 13299586272.

The previous prime is 13300012069. The next prime is 13300012127. The reversal of 13300012111 is 11121000331.

13300012111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13300012111 - 2⁷ = 13300011983 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300012091 and 13300012100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300012511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162015 + ... + 229888.

It is an arithmetic number, because the mean of its divisors is an integer number (3325109488).

Almost surely, 2^13300012111 is an apocalyptic number.

13300012111 is a deficient number, since it is larger than the sum of its proper divisors (425841).

13300012111 is an equidigital number, since it uses as much as digits as its factorization.

13300012111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 425840.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13300012111 its reverse (11121000331), we get a palindrome (24421012442).

The spelling of 13300012111 in words is "thirteen billion, three hundred million, twelve thousand, one hundred eleven".