133001001340061 has 2 divisors, whose sum is σ = 133001001340062. Its totient is φ = 133001001340060.

The previous prime is 133001001339971. The next prime is 133001001340063. The reversal of 133001001340061 is 160043100100331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124081108288900 + 8919893051161 = 11139170^2 + 2986619^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133001001340061 is a prime.

Together with 133001001340063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133001001340063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500500670030 + 66500500670031.

It is an arithmetic number, because the mean of its divisors is an integer number (66500500670031).

Almost surely, 2^{133001001340061} is an apocalyptic number.

It is an amenable number.

133001001340061 is a deficient number, since it is larger than the sum of its proper divisors (1).

133001001340061 is an equidigital number, since it uses as much as digits as its factorization.

133001001340061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 133001001340061 its reverse (160043100100331), we get a palindrome (293044101440392).

The spelling of 133001001340061 in words is "one hundred thirty-three trillion, one billion, one million, three hundred forty thousand, sixty-one".