Base | Representation |
---|---|
bin | 11110001111011010110111… |
… | …011010010011000010100010 |
3 | 122102220202220202201010222200 |
4 | 132033122313122103002202 |
5 | 114413042104302142234 |
6 | 1150511455352314030 |
7 | 40005002422262544 |
oct | 3617326732230242 |
9 | 572822822633880 |
10 | 133001034412194 |
11 | 39418470661113 |
12 | 12b005a93a2916 |
13 | 5929c364b05c0 |
14 | 24bb3da5dd694 |
15 | 10599dea19d99 |
hex | 78f6b76930a2 |
133001034412194 has 48 divisors (see below), whose sum is σ = 312600971467512. Its totient is φ = 40624684280064.
The previous prime is 133001034412189. The next prime is 133001034412243. The reversal of 133001034412194 is 491214430100331.
133001034412194 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 0 + 103 + 441 + 21 + 94 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 55361233703169 + 77639800709025 = 7440513^2 + 8811345^2 .
It is a super-2 number, since 2×1330010344121942 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2074349289 + ... + 2074413404.
Almost surely, 2133001034412194 is an apocalyptic number.
133001034412194 is an abundant number, since it is smaller than the sum of its proper divisors (179599937055318).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133001034412194 is a wasteful number, since it uses less digits than its factorization.
133001034412194 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4148762851 (or 4148762848 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 36.
The spelling of 133001034412194 in words is "one hundred thirty-three trillion, one billion, thirty-four million, four hundred twelve thousand, one hundred ninety-four".
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