1330011120014 has 4 divisors (see below), whose sum is σ = 1995016680024. Its totient is φ = 665005560006.

The previous prime is 1330011120001. The next prime is 1330011120017. The reversal of 1330011120014 is 4100211100331.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1330011120014² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330011119974 and 1330011120001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330011120017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332502780002 + ... + 332502780005.

It is an arithmetic number, because the mean of its divisors is an integer number (498754170006).

Almost surely, 2^{1330011120014} is an apocalyptic number.

1330011120014 is a deficient number, since it is larger than the sum of its proper divisors (665005560010).

1330011120014 is an equidigital number, since it uses as much as digits as its factorization.

1330011120014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 665005560009.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1330011120014 its reverse (4100211100331), we get a palindrome (5430222220345).

The spelling of 1330011120014 in words is "one trillion, three hundred thirty billion, eleven million, one hundred twenty thousand, fourteen".