Base | Representation |
---|---|
bin | 11110001111011010111101… |
… | …001011111100101110110100 |
3 | 122102220210011112001021102011 |
4 | 132033122331023330232310 |
5 | 114413042304104022400 |
6 | 1150511513133254004 |
7 | 40005005010032440 |
oct | 3617327513745664 |
9 | 572823145037364 |
10 | 133001131314100 |
11 | 39418510326a35 |
12 | 12b00615934304 |
13 | 5929c505aabca |
14 | 24bb409425820 |
15 | 10599e82ab8ba |
hex | 78f6bd2fcbb4 |
133001131314100 has 144 divisors (see below), whose sum is σ = 330213384990720. Its totient is φ = 45549179337600.
The previous prime is 133001131314097. The next prime is 133001131314127. The reversal of 133001131314100 is 1413131100331.
It is a super-3 number, since 3×1330011313141003 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2987491641 + ... + 2987536159.
It is an arithmetic number, because the mean of its divisors is an integer number (2293148506880).
Almost surely, 2133001131314100 is an apocalyptic number.
133001131314100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133001131314100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (165106692495360).
133001131314100 is an abundant number, since it is smaller than the sum of its proper divisors (197212253676620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133001131314100 is a wasteful number, since it uses less digits than its factorization.
133001131314100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49238 (or 49231 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 133001131314100 its reverse (1413131100331), we get a palindrome (134414262414431).
The spelling of 133001131314100 in words is "one hundred thirty-three trillion, one billion, one hundred thirty-one million, three hundred fourteen thousand, one hundred".
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