13300130114 has 4 divisors (see below), whose sum is σ = 19950195174. Its totient is φ = 6650065056.

The previous prime is 13300130113. The next prime is 13300130143. The reversal of 13300130114 is 41103100331.

13300130114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41103100331 = 4013 ⋅10242487.

It can be written as a sum of positive squares in only one way, i.e., 13217411089 + 82719025 = 114967^2 + 9095^2 .

It is a super-2 number, since 2×13300130114² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13300130092 and 13300130101.

It is not an unprimeable number, because it can be changed into a prime (13300130111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325032527 + ... + 3325032530.

Almost surely, 2^13300130114 is an apocalyptic number.

13300130114 is a deficient number, since it is larger than the sum of its proper divisors (6650065060).

13300130114 is an equidigital number, since it uses as much as digits as its factorization.

13300130114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6650065059.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13300130114 its reverse (41103100331), we get a palindrome (54403230445).

The spelling of 13300130114 in words is "thirteen billion, three hundred million, one hundred thirty thousand, one hundred fourteen".