13300130113 has 2 divisors, whose sum is σ = 13300130114. Its totient is φ = 13300130112.

The previous prime is 13300130111. The next prime is 13300130143. The reversal of 13300130113 is 31103100331.

13300130113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12770808064 + 529322049 = 113008^2 + 23007^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300130113 - 2¹ = 13300130111 is a prime.

It is a super-2 number, since 2×13300130113² (a number of 21 digits) contains 22 as substring.

Together with 13300130111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13300130111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650065056 + 6650065057.

It is an arithmetic number, because the mean of its divisors is an integer number (6650065057).

Almost surely, 2^13300130113 is an apocalyptic number.

It is an amenable number.

13300130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300130113 is an equidigital number, since it uses as much as digits as its factorization.

13300130113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13300130113 its reverse (31103100331), we get a palindrome (44403230444).

The spelling of 13300130113 in words is "thirteen billion, three hundred million, one hundred thirty thousand, one hundred thirteen".