13300130111 has 2 divisors, whose sum is σ = 13300130112. Its totient is φ = 13300130110.

The previous prime is 13300130087. The next prime is 13300130113. The reversal of 13300130111 is 11103100331.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (11103100331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13300130111 is a prime.

Together with 13300130113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300130113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650065055 + 6650065056.

It is an arithmetic number, because the mean of its divisors is an integer number (6650065056).

Almost surely, 2^13300130111 is an apocalyptic number.

13300130111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300130111 is an equidigital number, since it uses as much as digits as its factorization.

13300130111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 13300130111 its reverse (11103100331), we get a palindrome (24403230442).

The spelling of 13300130111 in words is "thirteen billion, three hundred million, one hundred thirty thousand, one hundred eleven".