13300311131320 has 64 divisors (see below), whose sum is σ = 29987686149120. Its totient is φ = 5309106474624.

The previous prime is 13300311131273. The next prime is 13300311131351. The reversal of 13300311131320 is 2313111300331.

It is a junction number, because it is equal to n+sod(n) for n = 13300311131291 and 13300311131300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 358258279 + ... + 358295401.

It is an arithmetic number, because the mean of its divisors is an integer number (468557596080).

Almost surely, 2^{13300311131320} is an apocalyptic number.

13300311131320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13300311131320 is an abundant number, since it is smaller than the sum of its proper divisors (16687375017800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300311131320 is a wasteful number, since it uses less digits than its factorization.

13300311131320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55444 (or 55440 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13300311131320 its reverse (2313111300331), we get a palindrome (15613422431651).

The spelling of 13300311131320 in words is "thirteen trillion, three hundred billion, three hundred eleven million, one hundred thirty-one thousand, three hundred twenty".