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1330041500335 = 5266008300067
BaseRepresentation
bin10011010110101100101…
…001101011001010101111
311201011001212201210100201
4103112230221223022233
5133242411111002320
62455002421134331
7165043445134432
oct23265451531257
94634055653321
101330041500335
11473081831019
1219593025a3a7
1398564c5cc42
1448535317819
15248e64ea70a
hex135aca6b2af

1330041500335 has 4 divisors (see below), whose sum is σ = 1596049800408. Its totient is φ = 1064033200264.

The previous prime is 1330041500327. The next prime is 1330041500353. The reversal of 1330041500335 is 5330051400331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330041500335 - 23 = 1330041500327 is a prime.

It is a super-2 number, since 2×13300415003352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133004150029 + ... + 133004150038.

It is an arithmetic number, because the mean of its divisors is an integer number (399012450102).

Almost surely, 21330041500335 is an apocalyptic number.

1330041500335 is a deficient number, since it is larger than the sum of its proper divisors (266008300073).

1330041500335 is an equidigital number, since it uses as much as digits as its factorization.

1330041500335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266008300072.

The product of its (nonzero) digits is 8100, while the sum is 28.

Adding to 1330041500335 its reverse (5330051400331), we get a palindrome (6660092900666).

The spelling of 1330041500335 in words is "one trillion, three hundred thirty billion, forty-one million, five hundred thousand, three hundred thirty-five".

Divisors: 1 5 266008300067 1330041500335