133011122101121 has 4 divisors (see below), whose sum is σ = 145103042292144. Its totient is φ = 120919201910100.

The previous prime is 133011122101111. The next prime is 133011122101133. The reversal of 133011122101121 is 121101221110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 133011122101121 - 2¹⁰ = 133011122100097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011122101093 and 133011122101102.

It is not an unprimeable number, because it can be changed into a prime (133011122101111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6045960095495 + ... + 6045960095516.

It is an arithmetic number, because the mean of its divisors is an integer number (36275760573036).

Almost surely, 2^{133011122101121} is an apocalyptic number.

133011122101121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

133011122101121 is a deficient number, since it is larger than the sum of its proper divisors (12091920191023).

133011122101121 is a wasteful number, since it uses less digits than its factorization.

133011122101121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12091920191022.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 133011122101121 its reverse (121101221110331), we get a palindrome (254112343211452).

The spelling of 133011122101121 in words is "one hundred thirty-three trillion, eleven billion, one hundred twenty-two million, one hundred one thousand, one hundred twenty-one".