Base | Representation |
---|---|
bin | 10011010110110000110… |
… | …011101001000100011101 |
3 | 11201011020201221000120021 |
4 | 103112300303221010131 |
5 | 133243031433101140 |
6 | 2455013351352141 |
7 | 165045252561634 |
oct | 23266063510435 |
9 | 4634221830507 |
10 | 1330111222045 |
11 | 473108121a71 |
12 | 19594b682651 |
13 | 98576531ba8 |
14 | 485406a651b |
15 | 248ec6bdb4a |
hex | 135b0ce911d |
1330111222045 has 8 divisors (see below), whose sum is σ = 1596223602360. Its totient is φ = 1064028887040.
The previous prime is 1330111222019. The next prime is 1330111222051. The reversal of 1330111222045 is 5402221110331.
It can be written as a sum of positive squares in 4 ways, for example, as 379568120281 + 950543101764 = 616091^2 + 974958^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1330111222045 - 219 = 1330110697757 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7413816 + ... + 7591105.
It is an arithmetic number, because the mean of its divisors is an integer number (199527950295).
Almost surely, 21330111222045 is an apocalyptic number.
It is an amenable number.
1330111222045 is a deficient number, since it is larger than the sum of its proper divisors (266112380315).
1330111222045 is a wasteful number, since it uses less digits than its factorization.
1330111222045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15022655.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1330111222045 its reverse (5402221110331), we get a palindrome (6732332332376).
The spelling of 1330111222045 in words is "one trillion, three hundred thirty billion, one hundred eleven million, two hundred twenty-two thousand, forty-five".
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