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1330112002143 = 31726080627493
BaseRepresentation
bin10011010110110000110…
…110100111100001011111
311201011020210101122122210
4103112300312213201133
5133243032133032033
62455013420211503
7165045262321161
oct23266066474137
94634223348583
101330112002143
11473108605081
1219594b999b93
1398576745ca2
144854082a931
15248ec7c4d63
hex135b0da785f

1330112002143 has 8 divisors (see below), whose sum is σ = 1877805179568. Its totient is φ = 834580079744.

The previous prime is 1330112002123. The next prime is 1330112002183. The reversal of 1330112002143 is 3412002110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1330112002143 - 214 = 1330111985759 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330112002123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13040313696 + ... + 13040313797.

It is an arithmetic number, because the mean of its divisors is an integer number (234725647446).

Almost surely, 21330112002143 is an apocalyptic number.

1330112002143 is a deficient number, since it is larger than the sum of its proper divisors (547693177425).

1330112002143 is a wasteful number, since it uses less digits than its factorization.

1330112002143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26080627513.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1330112002143 its reverse (3412002110331), we get a palindrome (4742114112474).

The spelling of 1330112002143 in words is "one trillion, three hundred thirty billion, one hundred twelve million, two thousand, one hundred forty-three".

Divisors: 1 3 17 51 26080627493 78241882479 443370667381 1330112002143