Base | Representation |
---|---|
bin | 11110001111100100010110… |
… | …100101001000001001110111 |
3 | 122102221202012200121111200112 |
4 | 132033210112211020021313 |
5 | 114413223440040140203 |
6 | 1150520302242533235 |
7 | 40005513024110432 |
oct | 3617442645101167 |
9 | 572852180544615 |
10 | 133011221021303 |
11 | 39421818742329 |
12 | 12b0257096721b |
13 | 592ab9aa46c61 |
14 | 24bbac545a819 |
15 | 1059dd8e896d8 |
hex | 78f916948277 |
133011221021303 has 2 divisors, whose sum is σ = 133011221021304. Its totient is φ = 133011221021302.
The previous prime is 133011221021267. The next prime is 133011221021339. The reversal of 133011221021303 is 303120122110331.
It is a balanced prime because it is at equal distance from previous prime (133011221021267) and next prime (133011221021339).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133011221021303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133011221021353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505610510651 + 66505610510652.
It is an arithmetic number, because the mean of its divisors is an integer number (66505610510652).
Almost surely, 2133011221021303 is an apocalyptic number.
133011221021303 is a deficient number, since it is larger than the sum of its proper divisors (1).
133011221021303 is an equidigital number, since it uses as much as digits as its factorization.
133011221021303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 133011221021303 its reverse (303120122110331), we get a palindrome (436131343131634).
The spelling of 133011221021303 in words is "one hundred thirty-three trillion, eleven billion, two hundred twenty-one million, twenty-one thousand, three hundred three".
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