13301131241381 has 2 divisors, whose sum is σ = 13301131241382. Its totient is φ = 13301131241380.

The previous prime is 13301131241339. The next prime is 13301131241383. The reversal of 13301131241381 is 18314213110331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11652562552225 + 1648568689156 = 3413585^2 + 1283966^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13301131241381 is a prime.

It is a super-2 number, since 2×13301131241381² (a number of 27 digits) contains 22 as substring.

Together with 13301131241383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13301131241383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650565620690 + 6650565620691.

It is an arithmetic number, because the mean of its divisors is an integer number (6650565620691).

Almost surely, 2^{13301131241381} is an apocalyptic number.

It is an amenable number.

13301131241381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301131241381 is an equidigital number, since it uses as much as digits as its factorization.

13301131241381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 13301131241381 in words is "thirteen trillion, three hundred one billion, one hundred thirty-one million, two hundred forty-one thousand, three hundred eighty-one".