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13301131241440 = 255771733736143
BaseRepresentation
bin1100000110001110100100…
…1100111110011111100000
31202002120112201001120112201
43001203221030332133200
53220411204044211230
644142242204102544
72541655301046040
oct301435114763740
952076481046481
1013301131241440
114268a8390a479
1215a9a21b34a54
137563a2c85a53
1433dac74b9720
15180ed62ed5ca
hexc18e933e7e0

13301131241440 has 384 divisors, whose sum is σ = 37022761746432. Its totient is φ = 4421956976640.

The previous prime is 13301131241401. The next prime is 13301131241467. The reversal of 13301131241440 is 4414213110331.

13301131241440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×133011312414403 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 13301131241399 and 13301131241408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2165247009 + ... + 2165253151.

It is an arithmetic number, because the mean of its divisors is an integer number (96413442048).

Almost surely, 213301131241440 is an apocalyptic number.

13301131241440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13301131241440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18511380873216).

13301131241440 is an abundant number, since it is smaller than the sum of its proper divisors (23721630504992).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13301131241440 is a wasteful number, since it uses less digits than its factorization.

13301131241440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6682 (or 6674 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13301131241440 its reverse (4414213110331), we get a palindrome (17715344351771).

The spelling of 13301131241440 in words is "thirteen trillion, three hundred one billion, one hundred thirty-one million, two hundred forty-one thousand, four hundred forty".