1330113203431 has 4 divisors (see below), whose sum is σ = 1408355156592. Its totient is φ = 1251871250272.

The previous prime is 1330113203423. The next prime is 1330113203437. The reversal of 1330113203431 is 1343023110331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330113203431 - 2³ = 1330113203423 is a prime.

It is a super-2 number, since 2×1330113203431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330113203396 and 1330113203405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330113203437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39120976555 + ... + 39120976588.

It is an arithmetic number, because the mean of its divisors is an integer number (352088789148).

Almost surely, 2^{1330113203431} is an apocalyptic number.

1330113203431 is a deficient number, since it is larger than the sum of its proper divisors (78241953161).

1330113203431 is an equidigital number, since it uses as much as digits as its factorization.

1330113203431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78241953160.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1330113203431 its reverse (1343023110331), we get a palindrome (2673136313762).

The spelling of 1330113203431 in words is "one trillion, three hundred thirty billion, one hundred thirteen million, two hundred three thousand, four hundred thirty-one".