Base | Representation |
---|---|
bin | 111101111100000100… |
… | …1000001100010000111 |
3 | 110201022211210111201012 |
4 | 1323320021001202013 |
5 | 4134402101242043 |
6 | 141034355352435 |
7 | 12416110325126 |
oct | 1737011014207 |
9 | 421284714635 |
10 | 133012134023 |
11 | 51456977a9a |
12 | 219415b271b |
13 | c709c47062 |
14 | 661b54dabd |
15 | 36d7502a18 |
hex | 1ef8241887 |
133012134023 has 2 divisors, whose sum is σ = 133012134024. Its totient is φ = 133012134022.
The previous prime is 133012133981. The next prime is 133012134053. The reversal of 133012134023 is 320431210331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133012134023 - 214 = 133012117639 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133012134023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133012134053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66506067011 + 66506067012.
It is an arithmetic number, because the mean of its divisors is an integer number (66506067012).
Almost surely, 2133012134023 is an apocalyptic number.
133012134023 is a deficient number, since it is larger than the sum of its proper divisors (1).
133012134023 is an equidigital number, since it uses as much as digits as its factorization.
133012134023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 133012134023 its reverse (320431210331), we get a palindrome (453443344354).
The spelling of 133012134023 in words is "one hundred thirty-three billion, twelve million, one hundred thirty-four thousand, twenty-three".
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