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1330130035 = 51320463539
BaseRepresentation
bin100111101001000…
…0010110001110011
310102200212121101101
41033102002301303
510211003130120
6335553145231
744650630063
oct11722026163
93380777341
101330130035
11622907423
1231155b217
131827571c0
14c89253a3
157bb9290a
hex4f482c73

1330130035 has 8 divisors (see below), whose sum is σ = 1718937360. Its totient is φ = 982249824.

The previous prime is 1330130027. The next prime is 1330130047. The reversal of 1330130035 is 5300310331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1330130035 - 23 = 1330130027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330129994 and 1330130021.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10231705 + ... + 10231834.

It is an arithmetic number, because the mean of its divisors is an integer number (214867170).

Almost surely, 21330130035 is an apocalyptic number.

1330130035 is a deficient number, since it is larger than the sum of its proper divisors (388807325).

1330130035 is a wasteful number, since it uses less digits than its factorization.

1330130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20463557.

The product of its (nonzero) digits is 405, while the sum is 19.

The square root of 1330130035 is about 36470.9478215195. The cubic root of 1330130035 is about 1099.7602879861.

Adding to 1330130035 its reverse (5300310331), we get a palindrome (6630440366).

The spelling of 1330130035 in words is "one billion, three hundred thirty million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 13 65 20463539 102317695 266026007 1330130035