1330131000047 has 2 divisors, whose sum is σ = 1330131000048. Its totient is φ = 1330131000046.

The previous prime is 1330131000043. The next prime is 1330131000049. The reversal of 1330131000047 is 7400001310331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1330131000047 - 2² = 1330131000043 is a prime.

Together with 1330131000049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330130999986 and 1330131000031.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330131000043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665065500023 + 665065500024.

It is an arithmetic number, because the mean of its divisors is an integer number (665065500024).

Almost surely, 2^{1330131000047} is an apocalyptic number.

1330131000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330131000047 is an equidigital number, since it uses as much as digits as its factorization.

1330131000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 23.

Adding to 1330131000047 its reverse (7400001310331), we get a palindrome (8730132310378).

The spelling of 1330131000047 in words is "one trillion, three hundred thirty billion, one hundred thirty-one million, forty-seven", and thus it is an aban number.