Base | Representation |
---|---|
bin | 11110001111100110001101… |
… | …101111000110000111100001 |
3 | 122102221221101000021101211000 |
4 | 132033212031233012013201 |
5 | 114413242033322414410 |
6 | 1150521232454342213 |
7 | 40005613410151530 |
oct | 3617461557060741 |
9 | 572857330241730 |
10 | 133013220123105 |
11 | 39422654126083 |
12 | 12b02a2a35a969 |
13 | 592b128c6852a |
14 | 24bbc34b60317 |
15 | 1059ea4720dc0 |
hex | 78f98dbc61e1 |
133013220123105 has 128 divisors (see below), whose sum is σ = 286153770470400. Its totient is φ = 57227680714752.
The previous prime is 133013220123073. The next prime is 133013220123137. The reversal of 133013220123105 is 501321022310331.
133013220123105 is a `hidden beast` number, since 1 + 3 + 301 + 3 + 220 + 123 + 10 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (133013220123073) and next prime (133013220123137).
It is not a de Polignac number, because 133013220123105 - 25 = 133013220123073 is a prime.
It is a super-2 number, since 2×1330132201231052 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 759931579 + ... + 760106591.
It is an arithmetic number, because the mean of its divisors is an integer number (2235576331800).
Almost surely, 2133013220123105 is an apocalyptic number.
133013220123105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133013220123105 is an abundant number, since it is smaller than the sum of its proper divisors (153140550347295).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133013220123105 is a wasteful number, since it uses less digits than its factorization.
133013220123105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222360 (or 222354 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 27.
Adding to 133013220123105 its reverse (501321022310331), we get a palindrome (634334242433436).
The spelling of 133013220123105 in words is "one hundred thirty-three trillion, thirteen billion, two hundred twenty million, one hundred twenty-three thousand, one hundred five".
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