Base | Representation |
---|---|
bin | 10011010110110110000… |
… | …111100100101111111111 |
3 | 11201011110221121100020112 |
4 | 103112312013210233333 |
5 | 133243222241131221 |
6 | 2455030253340235 |
7 | 165050414163353 |
oct | 23266607445777 |
9 | 4634427540215 |
10 | 1330200333311 |
11 | 473153456643 |
12 | 19597549767b |
13 | 9858bb32455 |
14 | 4854c461463 |
15 | 2490542215b |
hex | 135b61e4bff |
1330200333311 has 2 divisors, whose sum is σ = 1330200333312. Its totient is φ = 1330200333310.
The previous prime is 1330200333271. The next prime is 1330200333313. The reversal of 1330200333311 is 1133330020331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330200333311 - 210 = 1330200332287 is a prime.
Together with 1330200333313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330200333313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665100166655 + 665100166656.
It is an arithmetic number, because the mean of its divisors is an integer number (665100166656).
Almost surely, 21330200333311 is an apocalyptic number.
1330200333311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330200333311 is an equidigital number, since it uses as much as digits as its factorization.
1330200333311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 1330200333311 its reverse (1133330020331), we get a palindrome (2463530353642).
The spelling of 1330200333311 in words is "one trillion, three hundred thirty billion, two hundred million, three hundred thirty-three thousand, three hundred eleven".
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