Search a number
-
+
13302023340340 = 2257150847629873
BaseRepresentation
bin1100000110010001111001…
…1000000100000100110100
31202002122211212200220011201
43001210132120010010310
53220420020433342330
644142510512542244
72542016352546340
oct301443630040464
952078755626151
1013302023340340
1142693a1435599
1215aa030851984
137564b5a44017
1433db6db7a620
151810397b8eca
hexc191e604134

13302023340340 has 48 divisors (see below), whose sum is σ = 31925118339072. Its totient is φ = 4560656242176.

The previous prime is 13302023340329. The next prime is 13302023340341. The reversal of 13302023340340 is 4304332020331.

It is a happy number.

It is a super-3 number, since 3×133020233403403 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 13302023340299 and 13302023340308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13302023340341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20803644 + ... + 21433516.

It is an arithmetic number, because the mean of its divisors is an integer number (665106632064).

Almost surely, 213302023340340 is an apocalyptic number.

13302023340340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13302023340340 is an abundant number, since it is smaller than the sum of its proper divisors (18623094998732).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13302023340340 is a wasteful number, since it uses less digits than its factorization.

13302023340340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 780736 (or 780734 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 28.

Adding to 13302023340340 its reverse (4304332020331), we get a palindrome (17606355360671).

The spelling of 13302023340340 in words is "thirteen trillion, three hundred two billion, twenty-three million, three hundred forty thousand, three hundred forty".

Divisors: 1 2 4 5 7 10 14 20 28 35 70 140 150847 301694 603388 629873 754235 1055929 1259746 1508470 2111858 2519492 3016940 3149365 4223716 4409111 5279645 6298730 8818222 10559290 12597460 17636444 21118580 22045555 44091110 88182220 95014452431 190028904862 380057809724 475072262155 665101167017 950144524310 1330202334034 1900289048620 2660404668068 3325505835085 6651011670170 13302023340340