Base | Representation |
---|---|
bin | 10011010110110111011… |
… | …010011000001111101000 |
3 | 11201011112110110011021110 |
4 | 103112313122120033220 |
5 | 133243243320240130 |
6 | 2455032350510320 |
7 | 165051066531315 |
oct | 23266732301750 |
9 | 4634473404243 |
10 | 1330222040040 |
11 | 473164732193 |
12 | 1959808053a0 |
13 | 9859349267a |
14 | 485512b1d0c |
15 | 249072adab0 |
hex | 135b76983e8 |
1330222040040 has 64 divisors (see below), whose sum is σ = 4083472324800. Its totient is φ = 346476436992.
The previous prime is 1330222040003. The next prime is 1330222040057. The reversal of 1330222040040 is 400402220331.
It is a junction number, because it is equal to n+sod(n) for n = 1330222039989 and 1330222040016.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128892325 + ... + 128902644.
It is an arithmetic number, because the mean of its divisors is an integer number (63804255075).
Almost surely, 21330222040040 is an apocalyptic number.
1330222040040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1330222040040 is an abundant number, since it is smaller than the sum of its proper divisors (2753250284760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1330222040040 is a wasteful number, since it uses less digits than its factorization.
1330222040040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 257795026 (or 257795022 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 1330222040040 its reverse (400402220331), we get a palindrome (1730624260371).
The spelling of 1330222040040 in words is "one trillion, three hundred thirty billion, two hundred twenty-two million, forty thousand, forty".
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