Base | Representation |
---|---|
bin | 1100000110010011011011… |
… | …1000001101100110001100 |
3 | 1202002200220112012222000020 |
4 | 3001210312320031212030 |
5 | 3220421341202434012 |
6 | 44143015355502140 |
7 | 2542032503641533 |
oct | 301446670154614 |
9 | 52080815188006 |
10 | 13302434421132 |
11 | 426959248968a |
12 | 15aa126457950 |
13 | 75654cc650ac |
14 | 33dbac5c731a |
15 | 18106091aa8c |
hex | c1936e0d98c |
13302434421132 has 72 divisors (see below), whose sum is σ = 32762284341696. Its totient is φ = 4200299719776.
The previous prime is 13302434421121. The next prime is 13302434421137. The reversal of 13302434421132 is 23112443420331.
It is a super-2 number, since 2×133024344211322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13302434421093 and 13302434421102.
It is not an unprimeable number, because it can be changed into a prime (13302434421137) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39700563 + ... + 40034229.
It is an arithmetic number, because the mean of its divisors is an integer number (455031726968).
Almost surely, 213302434421132 is an apocalyptic number.
13302434421132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13302434421132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16381142170848).
13302434421132 is an abundant number, since it is smaller than the sum of its proper divisors (19459849920564).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13302434421132 is a wasteful number, since it uses less digits than its factorization.
13302434421132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 342915 (or 342894 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13302434421132 its reverse (23112443420331), we get a palindrome (36414877841463).
It can be divided in two parts, 13302 and 434421132, that added together give a palindrome (434434434).
The spelling of 13302434421132 in words is "thirteen trillion, three hundred two billion, four hundred thirty-four million, four hundred twenty-one thousand, one hundred thirty-two".
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