Base | Representation |
---|---|
bin | 10011010110111000110… |
… | …011110111110111111111 |
3 | 11201011121002121001212020 |
4 | 103112320303313313333 |
5 | 133243320322003130 |
6 | 2455034545411223 |
7 | 165051503122026 |
oct | 23267063676777 |
9 | 4634532531766 |
10 | 1330245500415 |
11 | 4731769a6327 |
12 | 195988639b13 |
13 | 985982b7b50 |
14 | 4855445b8bd |
15 | 24909394e10 |
hex | 135b8cf7dff |
1330245500415 has 16 divisors (see below), whose sum is σ = 2292115324128. Its totient is φ = 654890092416.
The previous prime is 1330245500359. The next prime is 1330245500417. The reversal of 1330245500415 is 5140055420331.
It is not a de Polignac number, because 1330245500415 - 211 = 1330245498367 is a prime.
It is a super-3 number, since 3×13302455004153 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330245500417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3410885704 + ... + 3410886093.
It is an arithmetic number, because the mean of its divisors is an integer number (143257207758).
Almost surely, 21330245500415 is an apocalyptic number.
1330245500415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1330245500415 is a deficient number, since it is larger than the sum of its proper divisors (961869823713).
1330245500415 is a wasteful number, since it uses less digits than its factorization.
1330245500415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6821771818.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 1330245500415 in words is "one trillion, three hundred thirty billion, two hundred forty-five million, five hundred thousand, four hundred fifteen".
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