Base | Representation |
---|---|
bin | 11110001111111000111011… |
… | …010011101001010100001100 |
3 | 122110000212020020202010101100 |
4 | 132033320323103221110030 |
5 | 114414104210340011022 |
6 | 1150534354305543100 |
7 | 40010224326441450 |
oct | 3617707323512414 |
9 | 573025206663340 |
10 | 133033312032012 |
11 | 3943012451a677 |
12 | 12b068b7044a90 |
13 | 592ccab6b2c22 |
14 | 24bcbbd32c660 |
15 | 105a77d5941ac |
hex | 78fe3b4e950c |
133033312032012 has 72 divisors (see below), whose sum is σ = 384498805064192. Its totient is φ = 37991681100000.
The previous prime is 133033312031959. The next prime is 133033312032041. The reversal of 133033312032012 is 210230213330331.
133033312032012 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 3 + 331 + 2 + 0 + 320 + 1 + 2 = 666.
It is a super-2 number, since 2×1330333120320122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 123327364 + ... + 124401387.
Almost surely, 2133033312032012 is an apocalyptic number.
133033312032012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133033312032012 is an abundant number, since it is smaller than the sum of its proper divisors (251465493032180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133033312032012 is a wasteful number, since it uses less digits than its factorization.
133033312032012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 247730899 (or 247730894 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 27.
Adding to 133033312032012 its reverse (210230213330331), we get a palindrome (343263525362343).
The spelling of 133033312032012 in words is "one hundred thirty-three trillion, thirty-three billion, three hundred twelve million, thirty-two thousand, twelve".
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