133052035 has 4 divisors (see below), whose sum is σ = 159662448. Its totient is φ = 106441624.

The previous prime is 133052009. The next prime is 133052069. The reversal of 133052035 is 530250331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530250331 = 13 ⋅40788487.

It is a cyclic number.

It is not a de Polignac number, because 133052035 - 2²⁵ = 99497603 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133051997 and 133052015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13305199 + ... + 13305208.

It is an arithmetic number, because the mean of its divisors is an integer number (39915612).

Almost surely, 2^133052035 is an apocalyptic number.

133052035 is a deficient number, since it is larger than the sum of its proper divisors (26610413).

133052035 is an equidigital number, since it uses as much as digits as its factorization.

133052035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26610412.

The product of its (nonzero) digits is 1350, while the sum is 22.

The square root of 133052035 is about 11534.8183774171. The cubic root of 133052035 is about 510.5134327009.

The spelling of 133052035 in words is "one hundred thirty-three million, fifty-two thousand, thirty-five".