13310203100111 has 4 divisors (see below), whose sum is σ = 14010740105400. Its totient is φ = 12609666094824.

The previous prime is 13310203100071. The next prime is 13310203100113. The reversal of 13310203100111 is 11100130201331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13310203100111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13310203100111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310203100113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350268502616 + ... + 350268502653.

It is an arithmetic number, because the mean of its divisors is an integer number (3502685026350).

Almost surely, 2^{13310203100111} is an apocalyptic number.

13310203100111 is a deficient number, since it is larger than the sum of its proper divisors (700537005289).

13310203100111 is an equidigital number, since it uses as much as digits as its factorization.

13310203100111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 700537005288.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13310203100111 its reverse (11100130201331), we get a palindrome (24410333301442).

The spelling of 13310203100111 in words is "thirteen trillion, three hundred ten billion, two hundred three million, one hundred thousand, one hundred eleven".