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133102110130000 = 24541117414347859
BaseRepresentation
bin11110010000111000111111…
…111111100011111101010000
3122110021102210220111121122121
4132100320333333203331100
5114421221110143130000
61151030133143544024
740015211240561554
oct3620707777437520
9573242726447577
10133102110130000
11394573192269a0
1212b180b745b014
135936623b1b44b
1424c226847b864
15105c4583e0b1a
hex790e3ffe3f50

133102110130000 has 1600 divisors, whose sum is σ = 398940506173440. Its totient is φ = 42435993600000.

The previous prime is 133102110129929. The next prime is 133102110130007. The reversal of 133102110130000 is 31011201331.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133102110130007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 319 ways as a sum of consecutive naturals, for example, 154950069571 + ... + 154950070429.

Almost surely, 2133102110130000 is an apocalyptic number.

133102110130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133102110130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199470253086720).

133102110130000 is an abundant number, since it is smaller than the sum of its proper divisors (265838396043440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133102110130000 is a wasteful number, since it uses less digits than its factorization.

133102110130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1046 (or 1025 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 133102110130000 its reverse (31011201331), we get a palindrome (133133121331331).

The spelling of 133102110130000 in words is "one hundred thirty-three trillion, one hundred two billion, one hundred ten million, one hundred thirty thousand".