13311214103021 has 2 divisors, whose sum is σ = 13311214103022. Its totient is φ = 13311214103020.

The previous prime is 13311214103009. The next prime is 13311214103023. The reversal of 13311214103021 is 12030141211331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7730568552100 + 5580645550921 = 2780390^2 + 2362339^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13311214103021 is a prime.

Together with 13311214103023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311214103023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655607051510 + 6655607051511.

It is an arithmetic number, because the mean of its divisors is an integer number (6655607051511).

Almost surely, 2^{13311214103021} is an apocalyptic number.

It is an amenable number.

13311214103021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311214103021 is an equidigital number, since it uses as much as digits as its factorization.

13311214103021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13311214103021 its reverse (12030141211331), we get a palindrome (25341355314352).

The spelling of 13311214103021 in words is "thirteen trillion, three hundred eleven billion, two hundred fourteen million, one hundred three thousand, twenty-one".