13311311102100 has 180 divisors, whose sum is σ = 47072740464288. Its totient is φ = 3226984488000.

The previous prime is 13311311102083. The next prime is 13311311102101. The reversal of 13311311102100 is 120111311331.

13311311102100 is a `hidden beast` number, since 1 + 3 + 311 + 31 + 110 + 210 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (180).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311311102101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 74609616 + ... + 74787815.

Almost surely, 2^{13311311102100} is an apocalyptic number.

13311311102100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13311311102100 is an abundant number, since it is smaller than the sum of its proper divisors (33761429362188).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311311102100 is a wasteful number, since it uses less digits than its factorization.

13311311102100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149397468 (or 149397452 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13311311102100 its reverse (120111311331), we get a palindrome (13431422413431).

The spelling of 13311311102100 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, one hundred two thousand, one hundred".