Base | Representation |
---|---|
bin | 11110010001000011010110… |
… | …001100111011010011111000 |
3 | 122110022111111011222010200002 |
4 | 132101003112030323103320 |
5 | 114421411333324304040 |
6 | 1151035211422132132 |
7 | 40016053454313131 |
oct | 3621032614732370 |
9 | 573274434863602 |
10 | 133113220150520 |
11 | 39460aaa57a835 |
12 | 12b1a298121048 |
13 | 59376a478759c |
14 | 24c29ddbcac88 |
15 | 105c8a8963a15 |
hex | 7910d633b4f8 |
133113220150520 has 32 divisors (see below), whose sum is σ = 299505644550000. Its totient is φ = 53245128200448.
The previous prime is 133113220150439. The next prime is 133113220150543. The reversal of 133113220150520 is 25051022311331.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8976356 + ... + 18622604.
Almost surely, 2133113220150520 is an apocalyptic number.
133113220150520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133113220150520 is an abundant number, since it is smaller than the sum of its proper divisors (166392424399480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133113220150520 is a wasteful number, since it uses less digits than its factorization.
133113220150520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9991247 (or 9991243 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 133113220150520 its reverse (25051022311331), we get a palindrome (158164242461851).
The spelling of 133113220150520 in words is "one hundred thirty-three trillion, one hundred thirteen billion, two hundred twenty million, one hundred fifty thousand, five hundred twenty".
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