Base | Representation |
---|---|
bin | 111101111111000110… |
… | …1111111101001010110 |
3 | 110201120221122221011100 |
4 | 1323332031333221112 |
5 | 4140104202202220 |
6 | 141052441050530 |
7 | 12421456120002 |
oct | 1737615775126 |
9 | 421527587140 |
10 | 133114100310 |
11 | 514a9491854 |
12 | 2196b786a46 |
13 | c7250c8839 |
14 | 662acd3702 |
15 | 36e1444d90 |
hex | 1efe37fa56 |
133114100310 has 48 divisors (see below), whose sum is σ = 358031035440. Its totient is φ = 34273055040.
The previous prime is 133114100267. The next prime is 133114100333. The reversal of 133114100310 is 13001411331.
133114100310 is a `hidden beast` number, since 1 + 3 + 311 + 41 + 0 + 0 + 310 = 666.
It is a super-2 number, since 2×1331141003102 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25498176 + ... + 25503395.
It is an arithmetic number, because the mean of its divisors is an integer number (7458979905).
Almost surely, 2133114100310 is an apocalyptic number.
133114100310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133114100310 is an abundant number, since it is smaller than the sum of its proper divisors (224916935130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133114100310 is a wasteful number, since it uses less digits than its factorization.
133114100310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51001613 (or 51001610 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 133114100310 its reverse (13001411331), we get a palindrome (146115511641).
The spelling of 133114100310 in words is "one hundred thirty-three billion, one hundred fourteen million, one hundred thousand, three hundred ten".
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