Base | Representation |
---|---|
bin | 11110010001000100011111… |
… | …000110101010000111101010 |
3 | 122110022121122102102201111222 |
4 | 132101010133012222013222 |
5 | 114421421334432302020 |
6 | 1151035533033222042 |
7 | 40016125665403304 |
oct | 3621043706520752 |
9 | 573277572381458 |
10 | 133114443244010 |
11 | 39461577a19aa8 |
12 | 12b1a579861922 |
13 | 593783aca6247 |
14 | 24c2ab840c974 |
15 | 105c92b011b25 |
hex | 79111f1aa1ea |
133114443244010 has 32 divisors (see below), whose sum is σ = 250024308076800. Its totient is φ = 50930609433088.
The previous prime is 133114443244001. The next prime is 133114443244021. The reversal of 133114443244010 is 10442344411331.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165854939 + ... + 166655601.
It is an arithmetic number, because the mean of its divisors is an integer number (7813259627400).
Almost surely, 2133114443244010 is an apocalyptic number.
133114443244010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133114443244010 is a deficient number, since it is larger than the sum of its proper divisors (116909864832790).
133114443244010 is a wasteful number, since it uses less digits than its factorization.
133114443244010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1523542.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 133114443244010 its reverse (10442344411331), we get a palindrome (143556787655341).
The spelling of 133114443244010 in words is "one hundred thirty-three trillion, one hundred fourteen billion, four hundred forty-three million, two hundred forty-four thousand, ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •