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13311543703 is a prime number
BaseRepresentation
bin11000110010110111…
…00000100110010111
31021100201000111002011
430121123200212113
5204230223344303
610040520325051
7650605153213
oct143133404627
937321014064
1013311543703
115711023897
1226b6013787
131341ab1ba3
14903ca5943
1552d99116d
hex3196e0997

13311543703 has 2 divisors, whose sum is σ = 13311543704. Its totient is φ = 13311543702.

The previous prime is 13311543689. The next prime is 13311543727. The reversal of 13311543703 is 30734511331.

It is a happy number.

13311543703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13311543703 - 25 = 13311543671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311543743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655771851 + 6655771852.

It is an arithmetic number, because the mean of its divisors is an integer number (6655771852).

Almost surely, 213311543703 is an apocalyptic number.

13311543703 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311543703 is an equidigital number, since it uses as much as digits as its factorization.

13311543703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11340, while the sum is 31.

The spelling of 13311543703 in words is "thirteen billion, three hundred eleven million, five hundred forty-three thousand, seven hundred three".