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133121020211 is a prime number
BaseRepresentation
bin111101111111010100…
…0011001000100110011
3110201121102200111110222
41323332220121010303
54140112440121321
6141053245243255
712421602000434
oct1737650310463
9421542614428
10133121020211
1151502388883
1221971b6352b
13c72667c45a
14662bbb548b
1536e1d603ab
hex1efea19133

133121020211 has 2 divisors, whose sum is σ = 133121020212. Its totient is φ = 133121020210.

The previous prime is 133121020183. The next prime is 133121020213. The reversal of 133121020211 is 112020121331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133121020211 - 230 = 132047278387 is a prime.

Together with 133121020213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133121020211.

It is not a weakly prime, because it can be changed into another prime (133121020213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560510105 + 66560510106.

It is an arithmetic number, because the mean of its divisors is an integer number (66560510106).

Almost surely, 2133121020211 is an apocalyptic number.

133121020211 is a deficient number, since it is larger than the sum of its proper divisors (1).

133121020211 is an equidigital number, since it uses as much as digits as its factorization.

133121020211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 133121020211 its reverse (112020121331), we get a palindrome (245141141542).

The spelling of 133121020211 in words is "one hundred thirty-three billion, one hundred twenty-one million, twenty thousand, two hundred eleven".