13312112110040 has 16 divisors (see below), whose sum is σ = 29952252247680. Its totient is φ = 5324844844000.

The previous prime is 13312112110039. The next prime is 13312112110049. The reversal of 13312112110040 is 4001121121331.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13312112109994 and 13312112110021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13312112110049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166401401336 + ... + 166401401415.

It is an arithmetic number, because the mean of its divisors is an integer number (1872015765480).

Almost surely, 2^{13312112110040} is an apocalyptic number.

13312112110040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13312112110040 is an abundant number, since it is smaller than the sum of its proper divisors (16640140137640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312112110040 is a wasteful number, since it uses less digits than its factorization.

13312112110040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332802802762 (or 332802802758 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13312112110040 its reverse (4001121121331), we get a palindrome (17313233231371).

The spelling of 13312112110040 in words is "thirteen trillion, three hundred twelve billion, one hundred twelve million, one hundred ten thousand, forty".